如何使用PHP从数组中排除空键？

When doing a query in data bank I can receive both arrays as result:

Array
(
    [] => 401
    [BETA] => 223
    [GAMMA] => 195
    [DELTA] => 189
)

Array
(
    [ALFA] => 294
    [BETA] => 223
    [GAMMA] => 195
    [DELTA] => 189
)

What can I do to exclude the entirely line when the key is empty?

I tried something like this, but without success:

foreach($array as $key => $value){
    if(array_key_exists($key, $value) && is_null($value[$key])) {
        unset($key);
    }
    $array = $value;
}

Many thanks in advance!

Since the key is an empty string you could either remove that specific key:

$test = array(''=>'test', 'test'=>'test');

unset($test['']);

print_r($test);

Or remove all keys that contain only whitespace:

function array_remove_blank_keys($array) {

    foreach ($array as $key => $value) {

        if (preg_match('/^\s*$/', $key)) {
            unset($array[$key]);
        }

    }

    return $array;

}

$test = array(''=>'test', 'test'=>'test');

print_r($test);
print_r(array_remove_blank_keys($test));

Keys are never empty. They would have a numeric index. So just check to see if the key is numeric then unset.

foreach($array as $key => $value){
    if(is_numeric($key)) {
        unset($key);
    }

}

and you don't need to do $array = $value;

The key is not null, it is an empty string. eg:

$foo = array(""=>"bar");
print_r($foo);

Output:

Array
(
    [] => bar
)

So you would want either empty($key) or $key == '' as your test, the difference being that empty() can match quite a few things.

Use the empty($var) function for evaluation. It considers these values empty and returns true if provided with one:

null: the null value,

'': empty string,

0: numeric zero. Only if it is not assigned by direct or indirect assignment such as $var=0 or $var=1-1. Note that the zero string ('0') is not empty,

array(): an empty array,

$var;: an unassigned variable,

false: value of false,

' ': just a space string.