I'm getting a gzipped File from an FTP Server that contains an xml. I want to gunzip it und write the xml as a file.
This is the code I'm using right now:
ftp_get($ftpCon, __DIR__."/../files/data.gz", $val, FTP_BINARY);
$srcName = __DIR__."/../files/data.gz";
$dstName = __DIR__."/../files/stuff.xml";
$command = 'gunzip -c '.$srcName.' > '.$dstName;
$escapedCommand = escapeshellcmd($command);
system($escapedCommand);
But the XML File will be printed out on the console and not written into a file. How can I write the data from the zipped file into an XML file?
The problem lies in your use of escapeshellcmd. If you look at this example, you'll see that your escaped command looks like this:
gunzip -c from/data.gz \> to/stuff.xml
But you don't want the > to be escaped. Since you have full control over the rest of the command, try escaping only the filenames (you don't have to if they're hard-coded like in your example).
Use the zlib extension: