在PHP中拉取值：{“atte”“：0，”eventid“：1，”userid“：1}

So far I've tried a couple of methods for pulling the data from the following array that is received from JAVA(After print_r($_POST)):

{"attending":0,"eventid":1,"userid":1}

But I am having no luck, as other ways I've found on SO and around the net are all slightly different (Surrounded by ' ' and [])

My code:

print_r($_POST);
$data = json_decode($_POST);

$userid = $data['userid'];
$eventid = $data['eventid'];
$attending = $data['attending'];

My question is: how do I correctly pull the values from the Post and assign them to values?

I'm new to PHP so please no rude comments.

I have also tried:

$data = json_decode($_POST, true);

As mentioned in the comments but now I get:

Warning: json_decode() expects parameter 1 to be string, array given in C:\xampp\htdocs\attendanceradio.php on line 9

var_dump($_POST);:

Array
                                                          (
                                                              [{"attending":0,"eventid":2,"userid":1}] => 
                                                          )
                                                          array(1) {
                                                            ["{"attending":0,"eventid":2,"userid":1}"]=>
                                                            string(0) ""
                                                          }

Full PHP code:

<?php

    $user = 'root';
    $pass = '';
    $db = 'testuser';

    $con=mysqli_connect('localhost', $user, $pass, $db) or die('Unable to connect');
    print_r($_POST['json']);
    var_dump($_POST);

    $json = json_decode(trim(key($_POST), '[]'), true);
        var_dump($json);
    $userid = $json['userid'];
    $eventid = $json['eventid'];
    $attending = $json['attending'];

    $statement = mysqli_prepare($con, 
    'INSERT INTO user_has_event(user_user_id, event_event_id, attendance)
        VALUES (?, ?, ?)
        ON DUPLICATE KEY UPDATE attendance = ?');

    mysqli_stmt_bind_param($statement, 'iii', $userid, $eventid, $attending);
    mysqli_stmt_execute($statement);

    mysqli_stmt_store_result($statement);
    mysqli_stmt_bind_result($statement, $userid, $eventid, $attending);

    mysqli_stmt_close($statement);

    mysqli_close($con);
?>

Based on your data something like the following should work?

<?php

$json = json_decode(trim(key($_POST), '[]'), true);

var_dump($json);

?>

The error message that Array was given instead of a string and according to the var_dump I can see that POST is returning an array.

If you want to decode the JSON string you have to point to add the array index where the string is located, so your code should look like:

$data = json_decode($_POST[0], true);

$userid = $data['userid'];
$eventid = $data['eventid'];
$attending = $data['attending'];