So I'm a bit stuck, and I've been given various solutions, none of which work. Any hotshot PHP folks out there? Here's the deal, I'm trying to get an image to display on my website, from another website, that has a randomly generated IMG. Though I'm actually trying to do this off a personal art site of mine, this example will serve perfectly. http://commons.wikimedia.org/wiki/Special:Random/File
A random image page with an image on it pops up with that link. Now, I'd like to display THAT random image, or whatever image comes up, on another site. The two possible solutions I have encountered is gathering an array of URL LINKS from a given link. And then re displaying that array as images on another site, like a: < a href="https
The code I get back from what I'm talking about looks like this:
Array
(
[0] => https ://kfjhiakwhefkiujahefawef/awoefjoiwejfowe.jpg
[1] => https ://oawiejfoiaewjfoajfeaweoif/awoeifjao;iwejfoawiefj.png
)
Instead of the print out however, I'd like the actual images displayed, well specifically array [0], but one thing at a time. The code that's actually doing this is:
<?php
/*
Credits: Bit Repository
URL: http://www.bitrepository.com/
*/
$url = 'http://commons.wikimedia.org/wiki/Special:Random/File';
// Fetch page
$string = FetchPage($url);
// Regex that extracts the images (full tag)
$image_regex_src_url = '/<img[^>]*'.
'src=[\"|\'](.*)[\"|\']/Ui';
preg_match_all($image_regex, $string, $out, PREG_PATTERN_ORDER);
$img_tag_array = $out[0];
echo "<pre>"; print_r($img_tag_array); echo "</pre>";
// Regex for SRC Value
$image_regex_src_url = '/<img[^>]*'.
'src=[\"|\'](.*)[\"|\']/Ui';
preg_match_all($image_regex_src_url, $string, $out, PREG_PATTERN_ORDER);
$images_url_array = $out[1];
echo "<pre>"; print_r($images_url_array); echo "</pre>";
// Fetch Page Function
function FetchPage($path)
{
$file = fopen($path, "r");
if (!$file)
{
exit("The was a connection error!");
}
$data = '';
while (!feof($file))
{
// Extract the data from the file / url
$data .= fgets($file, 1024);
}
return $data;
}
for($i=0; $i<count($arr1); $i++) {
echo '<img src="'.$arr1[$i].'">';
}
?>
Solution two, Use a file_get_contents command. Which is this:
<?php
$html =
file_get_contents("http://commons.wikimedia.org/wiki/Special:Random/File");
libxml_use_internal_errors(true);
$dom = new DOMDocument();
$dom->loadHTML($html);
$xpath = new DOMXPath($dom);
$image_src = $xpath->query('//div[contains(@class,"fullImageLink")]/a/img')
[0]->getAttribute('src') ;
echo "<img src='$image_src'><br>";
?>
However, there's unfortunately an error message I get: Fatal error: Cannot use object of type DOMNodeList as array in /home/wilsons888/public_html/wiki.php on line 11. Or, if I remove a "}" at the end, I just get a blank page.
I have been told that the above code will work, but with openssl extension included. Problem is, I have no idea how to do this. (I'm very new to PHP). Anyone know how to plug it in, so to speak? Thank you so much! I feel like I'm close, just missing the last element.
I was able to load the random image, and "print it" as an image directly (so you can embed the php file directly on the IMG tag) using this code:
<?php
$html = file_get_contents("http://commons.wikimedia.org/wiki/Special:Random/File");
$dom = new DOMDocument();
$dom->loadHTML($html);
$remoteImage = $dom->getElementById("file")->firstChild->attributes[0]->textContent;
header("Content-type: image/png");
header('Content-Length: ' . filesize($remoteImage));
echo file_get_contents($remoteImage);
?>
Get a new file called showImage.php and put this code in it:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<img src="test.php">
</body>
</html>
Next, go to your browser and get the showImage.php path, and will show a random image fromt he site you asked...