mysqli_query（）期望给出至少2个参数1

Please help me with the solution to this problem:

mysqli_query() expects at least 2 parameters 1 given.......on line 24

mysqli_query() expects at least 2 parameters 1 given.......on line 24

mysqli_query() expects at least 2 parameters 1 given.......on line 24

<?php
if (isset($_POST['submit'])) 
{

$db_server  = "localhost";
$db_user    = "root";
$db_pass    = "";
$db_name    = "rms_db";

$db = new mysqli($db_server, $db_user, $db_pass, $db_name);

if($db->connect_errno){
    echo "Could not connect to database";

}

//Import uploaded file to Database
$file_CSV = fopen($_FILES['filename']['tmp_name'], "r");

while (($data = fgetcsv($file_CSV, 1000, ",")) !== FALSE) {
    mysqli_query("INSERT into stinfo (ibsn, name, ftname,mtname, sex, birth,religion, nationality, phone,email, bio, address, joined)
    values('$data[0], '$data[1]', '$data[2]','$data[3]','$data[4]', '$data[5]', '$data[6]','$data[7]', '$data[8]', '$data[9]','$data[10]', '$data[11]', NOW())");

    }

fclose($file_CSV);

//print "Import done";
echo "<script type='text/javascript'>alert('Successfully Imported a CSV File for User!');</script>";
echo "<script>document.location='index.php'</script>";
//view upload form
}

?>

You forgot to send the $db in first param of mysqli_query($db, <your request>)

You've created a MySQLi object $db here:

$db = new mysqli($db_server, $db_user, $db_pass, $db_name);

You've used it here:

if($db->connect_errno){

So use it here:

$db->query("INSERT into stinfo (ibsn, name, ftname, mtname, sex, birth, religion, nationality, phone, email, bio, address, joined)
                        values ('$data[0], '$data[1]', '$data[2]', '$data[3]','$data[4]', '$data[5]', '$data[6]', '$data[7]', '$data[8]', '$data[9]', '$data[10]', '$data[11]', NOW())");