我想从我的数据库中获取数据，不包括我的部分数据

     if($city!='Others'){

            $posts = Post::orderby('id','desc')->where(['city'=>$city])->paginate(10);
    }
    else{
            $posts = Post::orderby('id','desc')->whereNotIn(['city'=>'Lahore'])->paginate(10);
    }
}

I have displayed some specific data now I want to display data other than those which were displayed before.

First if is showing normal data and I am trying to display remaining data in else part.

Thank you for all your help. The only thing required was to keep whereNotIn statement values in an array. Like this.

    if($city!='Others'){

            $posts = Post::orderby('id','desc')->where(['city'=>$city])->paginate(10);
    }
    else{
   $posts = Post::orderby('id','desc')->whereNotIn(['city',array('Lahore')->paginate(10);
    }
}

This is a guess based on how your database is setup.

EDIT based on reply (see: https://laravel.com/docs/5.5/queries#where-clauses and Laravel != operator in where not working):

if($company!='Others'){
        $posts = Post::orderby('id','desc')->where(['company'=>$company])->paginate(10);
        }
        else{
            $posts = Post::orderby('id','desc')->where('city', '<>', 'Lahore')->paginate(10);
        }

Does that help (take a look at the links)?

WhereNotIn will take array of value You also need to pass column name in it

if($city !='Others'){
    $posts = Post::orderby('id','desc')->where(['city'=>$city])->paginate(10);
}
else{
    $posts = Post::orderby('id','desc')->whereNotIn('city',['Lahore'])->paginate(10);
}