如何从字符串中替换变量名和变量值？

I have a Google Forms Prefilled URL

$input = "https://docs.google.com/forms/d/e/1FAIpQLSe8aZbfXa2IRRzK6hPTDKvAf_Oa8chTMrX8wkkYcuVHGs-vuA/viewform?usp=pp_url&entry.1064398956=NAME&entry.1318807391=TELEPHONE";
$pars = parse_url($input);
$values = $pars["query"];
$values = str_replace("entry.", "", $values);
$values = str_replace("usp=pp_url&", "", $values);

With this code I get values as

1064398956=NAME&1318807391=TELEPHONE

Because the numbers (entry id) are always different, I use default values (like NAME, TELEPHONE), and these would be storaged to mySQL database like this:

Id  ||  NAME       || VALUE
================================
1   || 1064398956  || 1318807391

To upload a row to that mysql database I have the query:

    INSERT INTO TABLE (ID, NAME, VALUE) VALUES (1, $NAME, $VALUE)

Based on the following string, how i can find values $NAME and $VALUE?

1064398956=NAME&1318807391=TELEPHONE

The @mario and @chris85 solution that worked:

$string = '1064398956=NAME&1318807391=TELEPHONE';
parse_str($string, $output);
print_r(array_flip($output));

This code will switch the var name whit the value ($VALUE variable with 'NAME' value)

function get_var_name($vars, $var)
{
  foreach ($vars as $name => $value) {
    if ($value === $var) {
      return $name;
    }
  }
  return false;
}

$NAME = "VALUE";
$$NAME = get_var_name(get_defined_vars(), $NAME);

echo $VALUE; // will print 'NAME'