检查文件夹中的所有图像并将第一个图像存储到阵列

public function set_array($set_value) {
  /*set empty class*/
  $tempclass = new stdClass();

  /*full Image path src*/
  $search_dir = "/domain/img/company/Image1-000000-016";

  /*open dir*/
  $images = glob("$search_dir/*.*");
  sort($images);

  /*loop thought dir and get first Image*/
  if (count($images) > 0) {
  /*get product imagepath and set as src*/
  $tempclass->src = $images[0];

  /*return all data to array*/
  $this->Imagedata[] = clone($tempclass);
  }

}

My intention was to check my folder image and store first image to Imagedata[], but I keep checking the Imagedata[] is empty, I don't know why. I checked the folderpath as well, it is correct so what did I do wrong?

maybe because you store your files in $files variable and then check for $images variable which is undefined?

I really suggest you to spend some time into turning on E_NOTICE errors in your PHP environment, they help you a great deal in catching this kind of mistakes (it happens to everyone)

After Question Edited:

I think the best way to get files in a directory is :

$directory = "/domain/img/company/Image1-000000-016";
$images = scandir ($directory);
$firstImage = $directory . $files[2];


//$tempclass->src = $firstImage;

if this didn't work check directory permission and check if exists at all?

Old Answer:

You are doing just something small wrong! There is no $images variable at all! I think :

if (count($images) > 0) {
   $tempclass->src = $images[0];
   //....
}

Must be :

if (count($files) > 0) {
   $tempclass->src = $files[0];
   //....
}