如何在此示例模型中制作控制器？

How to make a controller in this model and pass to view? Sorry I'm just new in using mvc oop. I just want to learn the basic. Kinda confused on controller, since I know the model will hold the queries on the database. I dont know how to pass or work on controller.

Am I doing it right way in Model and Controller? I just need some advice. On how to handle Model and Controller correctly.

And I'm not using any framework just php itself and mvc pattern.

Model

class userModel{

    public function __construct(){  
        $dbCon = new DbConnector();
        $this->dbCon = $dbCon->getConnection();
    }

    public function select(){
        $myQuery = "SELECT * FROM users;";
        $results = $this->dbCon->query($myQuery);
        return $results;
    }
}

controller

 require_once("../model/userModel.php");

    class userController{
    private $userModelSelector;

    public function __construct(){
       $this->userModelSelector = new userModel();
    }
}

you can rename this calss to User_model and create new class User in class User you can call class User_model by this way you can call model from controller

If you pass the while loop (from your previous question's code) to your select() method:

class userModel{

    public function __construct(){  
        $dbCon = new DbConnector();
        $this->dbCon = $dbCon->getConnection();
    }

    public function select(){
        $myQuery = "SELECT * FROM users;";
        $results = $this->dbCon->query($myQuery);

// I added this bit
      while($getUsers = $results->fetch_array()){
          echo $getUsers['username'] . "<br>";
      }
        return $results;
    }

}

and then use that method passed from your controller in the return:

$user = new userModel();
return $user->select();

it will work, given if this is what the question is about.