PHP preg_replace字符串[复制]

I was using ereg_replace function to replace all tags in my HTML with blank. Tags in my case look like this: {{AGE}} {{NAME}} {{EMAIL_ADDRESS}}

I was using this sentence (was removed in PHP 7):

$my_string = ereg_replace("\{\{[a-zA-Z_0-9]+\}\}", "", $my_string); 

Now I would like to use alternative sentence to ereg_replace and I tried with this:

$my_string = preg_replace("\{\{[a-zA-Z_0-9]+\}\}", "", $my_string); 

It throws out error. Looks like 1st parameter for preg is not same as for ereg. Can someone tell me how to fix it to replace all tags which have format {{something here}}

Thanks.

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With preg_*-functions, your expressions require a delimiter (some character at the beginning and end of your expression that tells the underlying engine where your expression ends and any optional modifiers begin).

Most developers use / for a delimiter, so:

$my_string = preg_replace("/\{\{[a-zA-Z_0-9]+\}\}/", "", $my_string);

Although I don't think the { and } characters have special meaning in regular expressions, so you might be able to get away with not escaping them:

$my_string = preg_replace("/{{[a-zA-Z_0-9]+}}/", "", $my_string);