调用函数变量里面的函数变量[重复]

This question already has an answer here:

$function = function($parameter) use ($variable)
{
  //Do some stuff
  $function($something); //When I do this i get variable undefined '$function'
}

How can I call the function?

I've already tried to call the parent or redefine the variable but i'd like a more compact solution than just redefining a whole new function and using that.

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The general trick here is to use () the Closure holding variable by reference:

$function = function($parameter) use ($variable, &$function) {
    //Do some stuff
    $function($something);
}