将PHP数组拆分为相等的列，并在前面的行中使用余数

I've been trying to figure out how to take an array of items and divide it into 4 html lists (that's my specific need but divide by X would be better), with the extra requirement that any remainders be added from the front.

This is different to array_chunk() which will do the following:

item 1    item 4    item 7    item10
item 2    item 5    item 8
item 3    item 6    item 9

Where in fact what I need is this:

item 1    item 4    item 7    item 9    
item 2    item 5    item 8    item 10
item 3    item 6

With array_chunk() I can get the first output with something like this answer but array_chunk() takes a number of items per chunk as an argument and just leaves the last chunk shorter than the rest.

<?php
$item_arr = array(1,2,3,4,5,6,7,8,9,10);

$col_cnt = 4;

$item_cnt = count($item_arr);
$row_cnt = ceil($item_cnt/$col_cnt);
$item_in_last_row = $item_cnt%$col_cnt;
$temp_cnt = $row_cnt-1;
$curr_cnt = $row_cnt;

$curr_item = 0;
for($i=0;$i<$row_cnt;$i++){
    $curr_cnt = $row_cnt;
    for($j=$i,$x=0,$k=1;$x<$col_cnt;$x++,$j+=$curr_cnt){
        if($curr_item == $item_cnt){
            break;
        }
        if($k > $item_in_last_row && $item_in_last_row != 0){
            $abc = $curr_cnt;
            $curr_cnt = $temp_cnt;
            $temp_cnt = $abc;
        }
        print $item_arr[$j]." ";
        $k++;
        $curr_item++;
    }
    print "<br>";
} 
?>

Output:

1 4 7 9
2 5 8 10
3 6