I'm trying to use CSS within PHP code but it seems that I can't use CSS in the way that I'm trying. why?
<?php
$username = "Daved";
$password = "hello!";
?>
<html>
<head>
</head>
<body>
<?php
echo "<div style="font-size: 32px; background-color:#f00; color:#fff; width:200px;">And Operation</div>";
if($username == "Daved" && $password == "hello!"){
echo "<p>The Password and UserName are correct!</p>";
}
else {
echo "<p>You are not a member!</p>";
}
?>
</body>
</html>
Ok, It's a true way to use CSS like this, or I must to try using style in another way?
Actual Problem is your echo statement. It should be noted that the echo prints whatever is in between " " or ''. Hence your statement echo "<div style="font-size: 32px; background-color:#f00; color:#fff; width:200px;">And Operation</div>"; is closing at style=". Hence your code is not working change it to echo "<div style='font-size: 32px; background-color:#f00; color:#fff; width:200px;'>And Operation</div>";. It will surely work.
Its possible but you made a mistake
echo "style=" font-size:32;
Php will search for the method font-size:32. It wilp not find it and this causes an error. Use "" to define the string and use ' ' for inline css:
echo"style='font-size:32px'";
Try this it may helps. I just modified your code little bit in the 1st echo. It just the issue of using quote operator. Thanks
<html>
<head>
</head>
<body>
<?php
echo '<div style="font-size: 32px; background-color:#f00; color:#fff; width:200px;">And Operation</div>';
if($username == "Daved" && $password == "hello!"){
echo "<p>The Password and UserName are correct!</p>";
}
else {
echo "<p>You are not a member!</p>";
}
?>
</body>
</html>