如果PHP上有2个文本字段的语句

I'm posting a username and password from an input form and using them to check my arrays if they are there. If both are present, i want to echo a success message and if not i want to output an error message.

My success part of the if statement is working but my error message isn't outputting when i try. Can someone please help me.

<html>
<head>
    <title> Half Term Project 3 </title>
</head>
<body>
    <div align="center">
    <h2> Half Term Project 3 </h2>
    <?

    $errormessage = "log in details incorrect";
    $successmessage = "You are logged in";

    $userNames[0]="Carolyne"; 
    $userNames[1]="Dave"; 
    $userNames[2]="Sharonda"; 
    $userNames[3]="Milton"; 
    $userNames[4]="Macie"; 
    $userNames[5]="Harriette";
    $userNames[6]="Gianna"; 
    $userNames[7]="Grant"; 
    $userNames[8]="Caryl"; 
    $userNames[9]="Genna"; 
    $userNames[10]="Carl";

    $passwords[0]="password"; 
    $passwords[1]="123456"; 
    $passwords[2]="master"; 
    $passwords[3]="1234"; 
    $passwords[4]="qwerty"; 
    $passwords[5]="12345"; 
    $passwords[6]="dragon"; 
    $passwords[7]="mustang"; 
    $passwords[8]="baseball"; 
    $passwords[9]="football"; 
    $passwords[10]="letmein";

    $enteredusername = $_POST["username"];
    $enteredpassword = $_POST["password"];


    for($x=0; $x<=10; $x++){
        if($enteredusername == $userNames[$x]){
            if($enteredpassword == $passwords[$x]){
            echo $successmessage;
            }
            else {
                echo $errormessage;
            }
        }
        else echo $errormessage;            
    }




    ?>
    </div>
</body>

I avise you to rewrite your code in this way:

$user_found = false;
for($x=0; $x<=10; $x++){
    if($enteredusername == $userNames[$x] && $enteredpassword == $passwords[$x]) {
        $user_found = true;
        break;
    }
}
if($user_found){
    echo $successmessage;
}
else {
    echo $errormessage;
}

Another way to achieve the same is to use in_array function:

if (in_array($enteredusername, $userNames) 
    && in_array($enteredpassword, $passwords)) {
    echo $successmessage;
} else {
    echo $errormessage;
}
***

<?php

for($x=0; $x<=10; $x++)
{
  if(($enteredusername == $userNames[$x]) && ($enteredpassword == $passwords[$x]))
{
    $message = "success";
    break;
}
else
{
$message = "failure";
}
}
echo $message;

?>


</div>

See if this helps you -

<html>
<head>
    <title> Half Term Project 3 </title>
</head>
<body>
    <div align="center">
    <h2> Half Term Project 3 </h2>
    <?php

    $errormessage = "log in details incorrect";
    $successmessage = "You are logged in";

    $userNames[0]="Carolyne"; 
    $userNames[1]="Dave"; 
    $userNames[2]="Sharonda"; 
    $userNames[3]="Milton"; 
    $userNames[4]="Macie"; 
    $userNames[5]="Harriette";
    $userNames[6]="Gianna"; 
    $userNames[7]="Grant"; 
    $userNames[8]="Caryl"; 
    $userNames[9]="Genna"; 
    $userNames[10]="Carl";

    $passwords[0]="password"; 
    $passwords[1]="123456"; 
    $passwords[2]="master"; 
    $passwords[3]="1234"; 
    $passwords[4]="qwerty"; 
    $passwords[5]="12345"; 
    $passwords[6]="dragon"; 
    $passwords[7]="mustang"; 
    $passwords[8]="baseball"; 
    $passwords[9]="football"; 
    $passwords[10]="letmein";

    $enteredusername = "Carolyn";
    $enteredpassword = "password";
    $is_exist = false;

    for($x=0; $x<=10; $x++){
        if($enteredusername == $userNames[$x] && $enteredpassword == $passwords[$x]){
            $is_exist = true;
            break;
        }
    }

    if($is_exist) echo $successmessage;
    else echo $errormessage;

    ?>
    </div>

And note: <?php ?> tag was wrong in your code.