mysql选择具有相同ID的行,并按另一列的顺序选择

+-------+-----------+------------+
| id    | sequence  | text       |
+-------+-----------+------------+
| 12345 | 01        | Hello, my  | 
| 12345 | 02        | name is CJ | 
| 54321 | 01        | Good morn  | 
| 54321 | 02        | ing! Sup!  | 
+-------+-----------+------------+

I am totally lost. There are 2 messages in these rows 1) "Hello, my name is CJ" and 2) "Good morning! Sup!"

How could I display both of these messages by selecting them by IDs and with correct order(sequence)?

So the results would be

"Hello, my name is CJ"

"Good morning! Sup!"

SELECT id,GROUP_CONCAT(text ORDER BY sequence  SEPARATOR ' ') AS messages
FROM table1
GROUP BY id;

Output

id      messages
12345   Hello, my name is CJ
54321   Good morning! Sup!

Demo

http://sqlfiddle.com/#!9/f38d19/5

GROUP_CONCAT() function

MySQL GROUP_CONCAT() function returns a string with concatenated non-NULL value from a group.

Syntax :

GROUP_CONCAT([DISTINCT] expr [,expr ...]
         [ORDER BY {unsigned_integer | col_name | expr}
             [ASC | DESC] [,col_name ...]]
         [SEPARATOR str_val])

TRY GROUP_CONCAT

SELECT id,GROUP_CONCAT(text SEPARATOR ' ')
FROM tableA
GROUP BY id;
select GROUP_CONCAT(text SEPARATOR ' ')
from table_name
group by id