I'm trying to post some form data and return results but I am having trouble getting this to work:
The javascript:
<script type="text/javascript">
$(document).ready(function () {
$("#sendthis").click(function () {
$.ajax({
type: "POST",
data: $('#theform').serialize(),
cache: false,
url: "form.php",
success: function (data) {
alert(data);
}
});
return false;
});
});
</script>
The HTML:
<form id="theform">
<input type="text" class="sized" name="name" id="name"><br />
<input type="text" class="sized" name="email" id="email">
</form>
<a href="#" id="sendthis">Submit</a>
The page to post to (form.php):
<?php
if (isset($_POST['name'])){
$result = $_POST['name'];
}
echo $result;
?>
Now, it is my understanding that when the form is submitted, it would post to form.php, and the input value of "name" would be returned in an alert box. However, I can't seem to get the form data posting (or maybe returning) correctly.
Is it a problem with $('#theform').serialize()
? Maybe something else?
Any help is much appreciated.
Try this and see if it works
<form id="theform" action="/form.php">
<input type="text" class="sized" name="name" id="name"/><br />
<input type="text" class="sized" name="email" id="email" /><br />
<input type="submit" name="submit" value="Submit" />
</form>
The jquery
$("#theform").on('submit', function () {
$.post($(this).attr('action'), $(this).serialize(), function(data) {
alert(data);
});
return false;
});
I would add an error callback to your ajax request to catch if there are issues being encountered during the post. Do you have a debugger like firebug that can show you what data is being posted (and where)?