I have the following code:
$fullImg = $_POST['img'];
$avatar_name = $log_username.md5(uniqid()).'_avatar.jpg';
$avatar_path = '../user/'.$log_username.'/';
$avatar_new = $avatar_path.$avatar_name;
$target_h = $target_w = 150;
$x = $_POST['x'];
$y = $_POST['y'];
$w = $_POST['w'];
$h = $_POST['h'];
$qual = 90;
$orig_image = imagecreatefromjpeg($fullImg);
$new_image = imagecreatetruecolor($target_w,$target_h);
imagecopyresampled($new_img,$orig_image,0,0,$x,$y,$target_w,$target_h,$w,$h);
imagejpeg($new_image,$avatar_new,$qual);
I have an error in my error_log that says:
Warning: imagecopyresampled() expects parameter 1 to be resource, null given
I'm guessing it has something to do with my $_POST['img'] variable being a full url:
http://domain.com/images/image.jpg
I have set allow_url_fopen to 1 in my php.ini file. i thought this might fix it.
It is only a full url because it is read by js as var img = _('uloadedImg').src; and despite this being set as ../images/image.jpg, var img = _('uloadedImg').src; still returns a full url.
Is there a way to get the src from the image without the full url in js? Or is there something wrong with my script other than that?
There is a type error, you are specifying $new_img instead of $new_image:
$new_image = imagecreatetruecolor($target_w,$target_h);
imagecopyresampled($new_img,$orig_image,0,0,$x,$y,$target_w,$target_h,$w,$h);
^
Try below:
imagecopyresampled($new_image,$orig_image,0,0,$x,$y,$target_w,$target_h,$w,$h);