如何从数组中获取特定数据？

Right now I have a problem with retrieving data form arrays, maybe it's really simple (probably it is) but I am struggling wiht it since morning and it appears, that my knowledge about PHP is worth nothing...so I have few arrays:

array( "name" => "Array 1",
    "type" => "array"),

array( "name" => "Array 2",
    "type" => "whatever"),

array( "name" => "Array 3",
    "type" => "whatever"),

array( "name" => "Array 4",
    "type" => "array"),

array( "name" => "Array 5",
    "type" => "whatever"),

What I need to do is to display 'name' of arrays of the 'array' type, I know I need a foreach loop but how to construct 'foreach ($arrays as $array) {' to get the desired result?

EDIT

Thanks for all the replies, but I tihnk I didn't make myself clear. I need to display "name" only when there is a "type" => "array" present within array, every other arrays' "name" should be omitted.

You'll need to do something like this:

foreach($arrays as $array) {
    if($array['type'] == 'array') {
        print($array['name']);
    }
}

An array_map will do

array_map(function ($v){ if($v['type']=="array"){echo $v['name']."<br>";}},$arr);

OUTPUT :

Array 1
Array 4

Demo

put the arrays into a "container" array first, then you can use that one...

<?php

$data = array(

    array( "name" => "Array 1",
        "type" => "array"),

    array( "name" => "Array 2",
        "type" => "whatever"),

    array( "name" => "Array 3",
        "type" => "whatever"),

    array( "name" => "Array 4",
        "type" => "array"),

    array( "name" => "Array 5",
        "type" => "whatever")
);

foreach($data as $array) {
    if($array['type'] == 'array') {
      print($array['name']);
    }
}