在php中调用存储过程（返回两个表）

I am working in a GUI tool development using php. There are STORED PROCEDURES already present in the database. Those stored procedures cannot be changed. (other tool dependency).

My Question: There is a procedure which returns two tables when called in mysql directly. (maybe 2 select statement inside it).

How can I use 'mysqli -- php' to display the data from two tables returned?

NOTE : Both table returned has same columns(name,id,status) in it

Make use of mysqli::use_result

$mysqli = new mysqli("localhost", "root", "password", "db_name");
if ($mysqli->connect_errno) {
    echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") ";
}

$query = "CALL sp_multiple results (?, ?)";
$stmt = $mysqli->prepare($query);

if (!$stmt) {
    echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
}

$stmt->bind_param("ss", $param1, $param2);

$stmt->execute();

/* get first result set */
if ($result1 = $mysqli->use_result()) {
    //fetch data
    $result1->close();
}

/* get second result set */
if ($result2 = $mysqli->use_result()) {
    //fetch data
    $result2->close();
}

$mysqli->close();