无论格式如何，都删除URL

Having a brain freeze...

Have a URL which may be in any of the formats :

http://url.com/stuff
url.com/somestuff
www.url.com/otherstuff
https://www.url.com/morestuff

You get the picture.

How do I remove the .com part to leave just the various 'stuff' parts ? For example, the above would end up :

stuff
somestuff
otherstuff
morestuff

This should do the trick for you!

<?php
$url = "http://url.com/stuff";

$querystring = preg_replace('#^(https|http)?(://)?(www.)?([a-zA-Z0-9-]+)\.[a-zA-Z]{2,6}/#', "", $url);

echo $querystring;

I submitted this answer because I'm not very fond of solutions using explode() to handle this. Maybe your query string contains more slashes so, you'd have to write exceptions for those cases.

You could achieve that using the following code:

$com_pos      = strpos($url, '.com/');
$stuff_part   = substr($url, $com_pos + 5);

Click here to see the working code.

You can use explode to make an array, then get the last element from the array.

$str = 'http://url.com/stuff';
$arr = explode('/', $str);
echo end($arr); // 'stuff'

preg_replace("/^(https?:\/\/)?[^\/]+/" ,"", $url);

$path = parse_url('http://url.com/stuff', PHP_URL_PATH);

If you leave the second parameter unspecified you can return an array including the domain etc.

Use explode function to divide the string.

<?php
$url = "http://url.com/stuff";
$stuff = explode("/", $url);
echo $stuff[sizeof($stuff) - 1];
?>

I used sizeof to access to last element.