Quick question regarding __callStatic()
in PHP;
class Test{
public static function __callStatic($method, $arguments){
echo $method . PHP_EOL;
}
public function __call($method, $arguments){
echo $method . PHP_EOL;
}
}
$test = new Test();
$test->foo();
$test->{'hello-world'}();
Test::bar();
Test::{'goodbye-universe'}();
Expected output:
foo
hello-world
bar
goodbye-universe
Actual output:
foo
hello-world
bar
PHP Parse error: syntax error, unexpected '{', expecting T_STRING or T_VARIABLE or '$' in - on line 18
Is this syntax not permissible, nor functionality achievable with __callStatic()
?
Note: Trying to get away with no temporary variables. The following will work:
$goodbyeUniverse = 'goodbye-universe';
Test::$goodbyeUniverse();
But I'm trying to avoid that.
This has been resolved in PHP 5.4
04 Aug 2011, PHP 5.4.0 Alpha 3
- Added features:
. Short array syntax, see UPGRADING guide for full details
(rsky0711 at gmail . com, sebastian.deutsch at 9elements . com, Pierre)
. Binary numbers format (0b001010). (Jonah dot Harris at gmail dot com)
. Support for Class::{expr}() syntax (Pierrick)
https://svn.php.net/repository/php/php-src/tags/php_5_4_0RC8/NEWS
I don't think the PHP parser can handle that currently. I cannot prove it just now, but I think it's a similar issue like the array-dereferencing-issue after function calls (callme()['arraykey']
).
you could invoke a static function via call_user_func().