如果存在，替换php中的字符串

I have a string in php that looks like this

$(window).load(function(){
  $('.someclass').click(function () {
    $(this).text("clicked");
  });
});

what i want is - if string contains $(window).load(function(){ then replace this and also the end braces }); with empty string ""

But if $(window).load(function(){ do not exist then do nothing.

Here is what i have tried:

if(strpos($str,"$(window).load(function(){") == -1){
  // do nothing
}
else{
     str_replace("$(window).load(function(){","",$str);
     // how do i replace the last }); with ""
}

If your code is nicely indented like that, this might just work for you:

$str = <<<EOM
$(window).load(function(){
  $('.someclass').click(function () {
    $(this).text("clicked");
  });
});
EOM;

$start = preg_quote('$(window).load(function(){');
$end = preg_quote('});');

$new = preg_replace("/^$start\s*(.*?)^$end/ms", '$1', $str);

print_r($new);

You will need regular expressions for this one if you can guarantee that the }); will be the last one. If so:

$str = preg_replace("#\$\(window\)\.load\(function\(\) \{(.*)\}\);#is","",trim($str));

Should do the trick.

If you cannot guarantee that the }); you want to replace will be the last occurence, you will have to walk through your code and count the braces. No other way, sadly :-(

$str = substr($str, 0, strlen($str) - 4);

This will remove the last 3 characters of the string.

Find the position of the last occurrence with strrpos ? Then maybe do a str_replace from that point with a limit of 1? You should check the modified string with an external call to something like JSlint to make sure you didnt create malformed code.

I think, a working way will be just to test for (window).load, and to add this :

str_replace('$(window).load', "var functionOnLoad = ", $str);

Don't forget to add a call to this function if you want it to be execute. Somethink like :

str_replace('</script>', "functionOnLoad();</script>", $str);