使用PHP将多个SQL列组合到HTML表的单个列中

Is it possible to combine data from multiple columns in a MySQL table into a single column in an HTML table, where each record will be a new row in the HTML table?

In this example, a table in MySQL has two columns (Col1, Col2). The data from Col1 is displayed in the first column in the HTML table. The data from Col2 in MySQL is displayed in the second column in the HTML table. In another words, the HTML table matches the layout of the MySQL table.

<?php
$con = new mysqli('domain', 'username', 'password', 'database');
$sql = "select * from table1";
$sql_query = mysqli_query($con, $sql);

while ($row = mysqli_fetch_array($sql_query)) {
  $col1 = $row['col1'];
  $col2 = $row['col2'];

  echo "<table>";
  echo "<tr>";
  echo "<td> $col1 </td>";
  echo "<td> $col2 </td>";
  echo "</tr>";
  echo "</table>";
}
?>

MySQL Table:

| - - - - | - - - - - - - |
| Col1    |    Col2       |
| - - - - | - - - - - - - |
| Blue    |    Car        |
| Green   |    Truck      |
| Yellow  |    Van        |
| - - - - | - - - - - - - |

HTML Table:

| - - - - | - - - - - - - |
| Column1 |    Column2    |
| - - - - | - - - - - - - |
| Blue    |    Car        |
| Green   |    Truck      |
| Yellow  |    Van        |
| - - - - | - - - - - - - |

If $col1 and $col2 are put inside of a single TD tag, this does get both $col1 and $col2 to display in Col1 in the HTML table. However, both $col1 and $col2 are displayed in the same cell.

<?php
$con = new mysqli('domain', 'username', 'password', 'database');
$sql = "select * from table1";
$sql_query = mysqli_query($con, $sql);

while ($row = mysqli_fetch_array($sql_query)) {
  $col1 = $row['col1'];
  $col2 = $row['col2'];

  echo "<table>";
  echo "<tr>";
  echo "<td> $col1 $col2 </td>";
  echo "</tr>";
  echo "</table>";
}
?>

HTML Table:

| - - - - - - - - - - - - |
| Column1                 |
| - - - - - - - - - - - - |
| Blue Car                |
| Green Truck             |
| Yellow Van              |
| - - - - - - - - - - - - |

Is it possible to echo $Col1 and $Col2 in Column1 of the HTML table and have each record be in its own row in the HTML table?

| - - - - - - - - - - - - |
| Column1                 |
| - - - - - - - - - - - - |
| Blue                    |
| Green                   |
| Yellow                  |
| Car                     |
| Truck                   |
| Van                     |
| - - - - - - - - - - - - |

No need to have two loops. It can be done in single loop. Separate the col1 and col2 values in different variables. and at the end print it.

<?php
$con = new mysqli('domain', 'username', 'password', 'database');
$sql = "select * from table1";
$sql_query = mysqli_query($con, $sql);
$str = "<table>";
$str_col2 = "";
while ($row = mysqli_fetch_array($sql_query)) {
  $col1 = $row['col1'];
  $col2 = $row['col2'];    

  $str .= "<tr><td> $col1 </td></tr>";
  $str_col2 .= "<tr><td> $col2 </td></tr>";
}
echo $str . $str_col2 . "</table>";
?>

Your HTML is valid, but not correct. This is might be the structure of your resultant table.

Make a new array where you store the col2 value for showing after all the col1 value. After completing the col1 value loop again for the second col2 values for the display.

$col2 = array();
echo "<table>";
while ($row = mysqli_fetch_array($sql_query)) {
  $col1 = $row['col1'];
  $col2[] = $row['col2'];

  echo "<tr>";
  echo "<td> $col1 </td>";
  echo "</tr>";
}
for($i = 0; $ < count($col2); $i++){
  echo "<tr>";
  echo "<td> $col2[$i] </td>";
  echo "</tr>";
}
echo "</table>";