在创建文本链接后,将该文本与我一起带到另一页

I've got a problem. Im making a list of stuff and everything on the list is a link that should link to the same page. I want to take that links name, text, whatever you want to call it to the next page but don't know how to do that.

Here's an example!

while($row = mysql_fetch_array($result)){

    <td><a href=uppsatserInfo.php>" . $row['name'] . "</a>

}

The " $row['name'] " generates all the data from the row "name" in the database. As you can see, im making a link out of everything that is printed out. The link is to the page "uppsatserInfo.php" and I want to take the name of the link with me to that page, but how do I do that?

You can pass the name of the page as a GET parameter to uppsatserInfo.php. Change this:

"<td><a href=uppsatserInfo.php>" . $row['name'] . "</a>"

to this:

"<td><a href='uppsatserInfo.php?name=" . urlencode($row['name']) . "'>" . $row['name'] . "</a>"

On uppsatserInfo.php, the variable

$_GET['name']

will have the name of the page.

Just append it to the URL in the querystring:

echo "<td><a href='uppsatserInfo.php?name=" . urlencode($row['name']) . "'>" . $row['name'] . "</a></td>";

You get in on uppsatserInfo.php like so:

$name = $_GET['name'];

You still need too verify it is a valid value on that page as a user can easily alter this data.