当我使用$ .getJSON时，我可以将变量发送到我的PHP代码吗？

I currently have some JQuery code where I send the variable 'name' to a PHP file, and that PHP file calls the data in row 'name'

//JQuery Code
$('#next').click(function() {
    $('#question > h1').load('/php/getQuestion.php', { 
        name: qty
    });
});

//PHP Code Below
$value = (integer)$_POST["name"];
$sql = "SELECT `question_id`, `question` FROM Question WHERE `question_id` = 
{$value}";

I want to do a similar call using JQuery's $.getJSON. Currently this is my code:

var requestAnswer = ($.getJSON('[URL HERE]'));

Is there any way I could send the value of 'name' to my PHP code and get only the JSON request from row: 'name'. Something like:

var requestAnswer = ($.getJSON('[URL HERE]'),{ name:2});

I know this example doesn't work.

You can add the query string into the url like that

$.getJSON('getQuestion.php?name=abc', function(data) {
//process data here
});

on Server side, use $_GET["name"] to retrieve parameter

Based on jQuery.getJSON() documentation:-

You can pass your data as the second parameter:

$.getJSON( url [, data] [, success(data, textStatus, jqXHR)] )

like below:-

$.getJSON( "Url", {name:2},function( data ) {
      //code based on data
});

Again the documentation says:-

"Data that is sent to the server is appended to the URL as a query string. If the value of the data parameter is a plain object, it is converted to a string and url-encoded before it is appended to the URL."

So you can retrieve it to php end by using:-

$_GET['name'];