PHP从数据库中获取数据并将数据放入字符串中

I am still new to PHP. I have tried a few stuff, but I just can't get it to work.

Question: I want all the data from my users table to be in a string, separated by comma. Then when the ID is 2 to be ; for net new row, so on and so forth. If someone can please help me.

$server = "localhost";
$user_name = "root";
$password = "";
$database = "users";

$conn = new mysqli($server, $user_name, $password, $database);
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT * FROM Users;";
$result = $conn ->query($sql);

while($row = mysqli_fetch_array( $result )) {
    $rows = implode (";",$result);
    $array = $rows;

    echo $array;
}

Question2: But if I want first row of DB data to be, separated and then at the end with a ;. How would I do that?

Output: The output of this code is: Warning: implode(): Invalid arguments passed

Let's say your user table has 2 fields Firstname and Lastname. What I understood from your question is you want your output to be something like

$array = ['steve,jobs;', 'mark,zukerberg;'];

To achieve this you can append ';' at the end of the string.

while($row = mysqli_fetch_array( $result )) {
     $rows = implode(',',$row) . ';'; //you have named this variable $rows but it is going to have data of a single row
     $array = $rows; //you could directly var_dump($rows) instead of assigning it to a new variable
     echo $array; //you could rather use var_dump($array) for this
}

You've simply used the wrong variable in your call to ìmplode.

You've assigned all the columns as an array to $row - but you're trying to implode $result.

Update that line to this:

$rows = implode(";", $row);