I tried so hard and got so far but in the end it doesn't work!!
What I would like to do achieve is the following: I've got a preg_replace_callback function where I want to address my "dictionary" function.
I use my own "dictionary" tag:
<[general,username]>
<[general,username,1]>
this should call my function "dictionary". The function with it's ararguments is: dictionary($search,$section,$upper=null)
$search = filename
$section = array key
$upper = (int) 1 to 3
my callback function calls the function with the values from the "dictionary" tags.
for <[general,username]> I need
- $search = general
- $section = username
- $upper = null
but for <[general,username,1]> I want
- $search = general
- $section = username
- $upper = 1
I want my regular expression to always match 2 arguments (search and section) but have a third optional argument.
My regex:
/\<\[([^\[]+)\,([^\[]+)(\,[0-2])?\]\>/
but this doesn't work correctly. I get the following results:
for <[general,username]> I get
[0] => <[general,username]>
[1] => general
[2] => username
for <[general,username,1]> I get
[0] => <[general,username,1]>
[1] => general,username
[2] => 1
but I would like
[0] => <[general,username,1]>
[1] => general
[2] => username
[3] => 1
What am I doing wrong??
Try this out:
/\<\[([^\,]+)\,([^\,]+)(?:\,(\d+))?\]\>/
- Item[0] => whole matching text - Item[1] => general - Item[2] => username - Item[3] => upper (if match)
The regex is greedy by default, so the first group is matching the first comma as well. Try this instead:
/\<\[([^\[,]+)\,([^\[,]+)(?:\,([0-2]))?\]\>/
Exclude the comma from the range of the second group....
Or, assuming the first 2 terms are alphanumeric only:
\<\[(\w+)\,(\w+)\,?(\d+)?\]\>