This is my program :
$newEndingDate = strtotime(date("Y-m-d", strtotime($row['startdate']))."+1 year");
echo $newEndingDate;
this is my error
1332441000
whats the error
The strtotime() function returns an UNIX Timestamp : the number of seconds since 1970-01-01.
The number you are getting is not an error : it just means that 1332441000 seconds have passed since 1970.
If necessary, you can use the date() function to format that timestamp, to get a string that looks a bit more user-friendly.
For instance :
echo date('Y-m-d H:i:s', $newEndingDate);
should get you the following result :
2012-03-22 19:30:00
It is the return value of strtotime function, which is a UNIX timestamp. The seconds passed since 01/01/1970
I think this is you would like to get:
$newEndingDate = date('Y-m-d', strtotime('+ 1 year', strtotime($row['startdate'])));
Try using mktime to do what you want. Assume $row['startdate'] == '2011-01-01'
$mydate = strtotime($row['startdate']);
$newEndingDate = mktime(date("H", $mydate), date("i", $mydate), date("s", $mydate), date("n", $mydate), date("j", $mydate), date("Y", $mydate) + 1);
echo date('Y-m-d', $newEndingDate); //2012-01-01
What you are doing will not give you the result you're after because you can't do the following:
strotime('2011-01-01+1 year');
Try this instead:
$mydate = strtotime($row['startdate']);
$newEndingDate = date('Y-m-d', strtotime("+1 year", $mydate));
echo $newEndingDate; //2012-01-01
you dont get an error, you get the timestamp of all the seconds that have passed since 1970/01/01
if you need a readable format try:
$date = date("Y-m-d H:i:s", $newEndingDate);