I have a problem in calling a function that the name is being stored in an array.
class tempClass {
function someFunction() {
$tempArray = array('functionName' => 'tempFunction');
$tempArray['functionName']();
}
function tempFunction() {
echo "inside function";
}
}
It gives me an error:
"Fatal error: Call to undefined function tempFunction() in /..... line..".
Line number is the line where the function is being called, $tempArray['functionName']();
But if called the method_exists()
, it shows that the method is exists. It is very confusing. Can anyone please help me out? Thanks.
Use call_user_func() , like this:
call_user_func($tempArray['functionName']);
UPDATE:
As you want to call a method of a class from inside that class, use the following instead:
call_user_func(array($this, $tempArray['functionName']));
See working demo
Well you ask if the method exists inside the class or object, but you call it without that scope. That won't work...
Try this instead:
call_user_method($tempArray['functionName'],$this);
Just saw that call_user_method()
is depreciated. Use call_user_func()
as answered by Nelson instead.