为什么这个准备好的语句会抛出错误？

Having learnt the basics of PHP and MySQL, I am now learning how to protect against SQL injection attacks by using prepared statements. I have the following code:

for ($i = 0; $i < $delegateno ;$i++){

        $q = "INSERT INTO delegates (delegate_id,booker_name, booker_email, booker_tel, booker_company, delegate_name, delegate_email, delegate_tel) VALUES (NULL, ?, ?, ?, ?, ?, ?, ? )";//Insert delegate information into delegate tables
        $stmt = mysqli_query($dbc, $q);
        mysqli_stmt_bind_param($stmt,'sssssss', $fullname, $email, $tel, $company,$delegatename[$i],$delegateemail[$i],$delegatetel[$i]);
        mysqli_stmt_execute($stmt);
}

However, this throws:

Notice: Query: INSERT INTO delegates (delegate_id,booker_name, booker_email, booker_tel, booker_company, delegate_name, delegate_email, delegate_tel) VALUES (NULL, ?, ?, ?, ?, ?, ?, ? )
MySQL Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?, ?, ?, ?, ?, ?, ? )'

What am I doing wrong?

Because you're executing the raw query containing the placeholders. You need to prepare() the query first.

This is how it goes (usually): prepare -> bind_param -> execute -> fetch.

Change:

$stmt = mysqli_query($dbc, $q);

to:

$stmt = mysqli_prepare($dbc, $q);