I have a web page source code that I want to use in my project. I want to use an image link in this code. So, I want to reach this link using regex in PHP.
That's it:
img src="http://imagelinkhere.com" class="image"
There is only one line like this. My logic is to get the string between
="
and
" class="image"
characters.
How can I do that with REGEX? Thank you very much.
Don't use Regex for HTML .. try DomDocument
$html = '<html><img src="http://imagelinkhere.com" class="image" /></html>';
$dom = new DOMDocument();
$dom->loadHTML($html);
$img = $dom->getElementsByTagName("img");
foreach ( $img as $v ) {
if ($v->getAttribute("class") == "image")
print($v->getAttribute("src"));
}
Output
http://imagelinkhere.com
Try using preg_match_all, like this:
preg_match_all('/img src="([^"]*)"/', $source, $images);
That should put all the URL's of the images in the $images variable. What the regex does is find all img src bits in the code and matches the bit between the quotes.
There is several ways to do so :
1.you can use SimpleHTML Dom Parser which I prefer with simple HTML
2.you can also use preg_match
$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" class="image" />';
$array = array();
preg_match( '/src="([^"]*)"/i', $foo, $array ) ;
see this thread
Using
.*="(.*)?" .*
with preg replace gives you only the url in the first regex group (\1).
So complete it would look like
$str='img src="http://imagelinkhere.com" class="image"';
$str=preg_replace('.*="(.*)?" .*','$1',$str);
echo $str;
-->
http://imagelinkhere.com
Edit: Or just follow Baba's advice and use DOM Parser. I'll remember that regex will give you headaches when parsing html with it.
preg_match("/(http://+.*?")/",$text,$matches);
var_dump($matches);
The link would be in $matches.
I can hear the sound of hooves, so I have gone with DOM parsing instead of regex.
$dom = new DOMDocument();
$dom->loadHTMLFile('path/to/your/file.html');
foreach ($dom->getElementsByTagName('img') as $img)
{
if ($img->hasAttribute('class') && $img->getAttribute('class') == 'image')
{
echo $img->getAttribute('src');
}
}
This will echo only the src attribute of an img tag with a class="image"