在ajax中发送多个值

multiple value send search.php send two value search_word and search_word1. but both value is not display

var search_word = $("#search_box").val();
var search_word1 = $("#check_id").val();
var dataString = 'search_word='+ search_word;
if(search_word=='')
{
}
else
{
$.ajax({
type: "GET",
url: "include/search.php",
data: dataString,

search.php

   if(isset($_POST['search_word'])){

$serach_word = $_POST['search_word'];
$serach_word1 = $_POST['search_word1'];
    echo "$serach_word<br/>$serach_word1";

}

so Please Help.

data has to be a javascrpt object:

data: {
   search_word: search_word,
   search_word1: search_word1
}

Use Ajax POST method:

$.ajax({
    type: "POST", 
    url: "some.php", 
    data: {name: "John", location: "Boston"} 
}).done(
    function(msg) {
        alert("Data Saved: " + msg);
    }
);

if(search_word=='')
{
}
else
{
$.ajax({
type: "GET",
url: "include/search.php",
data: { 
         search_word: $("#search_box").val(),
         search_word1 :$("#check_id").val()
      }

Apart form David Fregoli answer you can also,send data in query string form,as you are using GET Method

 url: "include/search.php?search_word="+search_word+"&search_word1="+search_word1,

jQuery simplifies the task. The syntax is

$.get("include/search.php",{search_word:search_word,search_word1:search_word},function(response)
{
   alert(response);
});

For more details visit https://api.jquery.com/jQuery.get/

You can send selected data:

var test = 'yes, this is test string';
...
data: {
     testValue: test,
     filter: $('#form').find('#name_filter').val()
}

You can even serialize whole form in javascript

data: {
     filter: $('#form').serialize();
}

and deserialize it in PHP with simple code

$values = array();
parse_str($_POST['filter'], $values);

And $values will be full of inputs/select/checkbox values :)

You can try using $.param(dataString)

 var dataString: {
       search_word: $("#search_box").val(),
       search_word1: $("#check_id").val()
    }

if(dataString)
{
$.ajax({
type: "GET",
url: "include/search.php",
data: $.param(dataString)
});
}

In Server:

 if(isset($_POST['dataString'])){   
$serach_word = $dataString['search_word'];
$serach_word1 = $dataString['search_word1'];
    echo "$serach_word<br/>$serach_word1";
}