Shell脚本按顺序从1-9和A-Z传递字符

I need to pass a character to a php script in a bash script. I want to do this in a loop. it will start with '1' until '9' and than it will continue with 'A' to 'Z'. I've found that bash recognizes character's by their octal ASCII code. I think the code will look like this:

while true
do
      #There will be a second loop for character iteration here I suppose 
      php index.php char
      #end of the second loop
done

*char variables used above is the iterator and the parameter for the php script

Thank you!

You can do this:

for char in 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
do
    php index.php "$char"
done

No need to use the ASCII code here, a for loop will do the trick:

for char in {{1..9},{A..Z}} ; do
    php index.php $char
done