正则表达式返回空字符串

I have following code:

preg_match_all('/"([^"]*)"/', $json , $results);
var_dump($json);var_dump($results);die();

At this point a dump of $json has

string(423) "{"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX355_.jpg";[355,266],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX425_.jpg":[425,319],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX466_.jpg":[466,350],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX450_.jpg":[450,338],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL.jpg":[500,375]}"

I’m trying to get the links. I’ve tried json_decode but I get error number 4 which is incorrect syntax. There are no invisible characters in front or after the JSON on the string. Without luck i decided to try to regex my way into it but the above code returns

array(2) { [0]=> array(0) { } [1]=> array(0) { } }

Any help to get the first first would be greatly appreciated.

Ok, as some of you noted this is basically a hack to get it to work no matter what. If you are interested in doing it right here’s the full info:

$ch = curl_init("http://www.amazon.com/gp/product/B00BEL2G4C/ref=s9_wish_gw_d31_g21_i3?pf_rd_m=ATVPDKIKX0DER&pf_rd_s=desktop-1&pf_rd_r=1VPYMKFSFN5BRHD4AD3W&pf_rd_t=36701&pf_rd_p=1970559082&pf_rd_i=desktop");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_COOKIESESSION, true );
curl_setopt($ch, CURLOPT_COOKIEJAR, "cookies.txt" );
curl_setopt($ch, CURLOPT_COOKIEFILE, "cookies.txt" );
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:25.0) Gecko/20100101 Firefox/25.0");
$curl_scraped_page = curl_exec($ch);

$html = $html->load($curl_scraped_page);
$json = $html->find('#imageBlock', 0)->children[0]->children[0]->children[1]->children[1]->children[0]->children[2]->children[0]->children[0]->children[0]->children[0]->children[0]->attr['data-a-dynamic-image'];

$json = utf8_encode($json);
var_dump(json_decode($json));var_dump(json_last_error());die();

I know that Amazon has an API but they are annoying and will only let you use it if you are an affiliate and they don’t accept under construction websites as affiliates so I’m just trying to get this out and will change it to the API once site goes live and gets approved for Amazon affiliates.

The URL is actually dynamic, just used a static one for testing purposes. I would love to find a JSON solution as that would be much cleaner.

Not sure why it isn't working. This works for me:

<?php

$json ='{"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX355_.jpg":           [355,266],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX425_.jpg":[425,319],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX466_.jpg":[466,350],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX450_.jpg":[450,338],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL.jpg":[500,375]}';

 preg_match_all('/"([^"]*)"/', $json , $results);
 var_dump($json);var_dump($results);die();
?>

The output is:

    gregp:~ greg$ php ./test.preg.php 
string(373) "{"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX355_.jpg":[355,266],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX425_.jpg":[425,319],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX466_.jpg":[466,350],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX450_.jpg":[450,338],"http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL.jpg":[500,375]}"
array(2) {
  [0]=>
  array(5) {
    [0]=>
    string(65) ""http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX355_.jpg""
    [1]=>
    string(65) ""http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX425_.jpg""
    [2]=>
    string(65) ""http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX466_.jpg""
    [3]=>
    string(65) ""http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX450_.jpg""
    [4]=>
    string(57) ""http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL.jpg""
  }
  [1]=>
  array(5) {
    [0]=>
    string(63) "http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX355_.jpg"
    [1]=>
    string(63) "http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX425_.jpg"
    [2]=>
    string(63) "http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX466_.jpg"
    [3]=>
    string(63) "http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL._SX450_.jpg"
    [4]=>
    string(55) "http://ecx.images-amazon.com/images/I/51Lg%2Bd4cqRL.jpg"
  }
}

Just do a non-greedy match between the "'s

preg_match_all('/"(.*?)"/', $json , $results);
var_dump($json);var_dump($results);die();

Do this -

$parsed = json_decode($json, true);
foreach($parsed as $row=>$value){
    echo $row .'<br>';
}

EXAMPLE

So I had to do $json = preg_replace('/"/', '"', $json); before calling the decode and that fixed my issue.