I'd like to be able to return an array with a list of all images (src="" values) from html
[0] = "images/header.jpg" [1] = "images/person.jpg"
is there a regular expression that can do this?
Many thanks in advance!
/src="([^"]+)"/
The image will be in group 1.
Example:
preg_match_all('/src="([^"]+)"/', '<img src="lol"><img src="wat">', $arr, PREG_PATTERN_ORDER);
Returns:
Array
(
[0] => Array
(
[0] => src="lol"
[1] => src="wat"
)
[1] => Array
(
[0] => lol
[1] => wat
)
)
Welcome to the world of the millionth "how to exactract these values using regex" question ;-) I suggest to use the search tool before seeking an answer -- here is just a handful of topics that provide code to do exactly what you need;
Here is a more polished version of the regular expression provided by Håvard:
/(?<=src=")[^"]+(?=")/
This expression uses Lookahead & Lookbehind Assertions to get only what you want.
$str = '<img src="/img/001.jpg"><img src="/img/002.jpg">';
preg_match_all('/(?<=src=")[^"]+(?=")/', $str, $srcs, PREG_PATTERN_ORDER);
print_r($srcs);
The output will look like the following:
Array
(
[0] => Array
(
[0] => /img/001.jpg
[1] => /img/002.jpg
)
)
I see that many peoples struggle with Håvard's post and <script> issue. Here is same solution on more strict way:
<img.*?src="([^"]+)".*?>
Example:
preg_match_all('/<img.*?src="([^"]+)".*?>/', '<img src="lol"><img src="wat">', $arr, PREG_PATTERN_ORDER);
Returns:
Array
(
[1] => Array
(
[0] => "lol"
[1] => "wat"
)
)
This will avoid other tags to be matched. HERE is example.