从url获取变量给出错误

I am using this code to get the variable iduser to use it in php as part of another url ( line2). But it gives me the following error "Parse error: syntax error, unexpected T_VARIABLE in" can you please show me my mistake.

 <?php  
 $iduser=$_GET['iduser'];
 $currsiteurl = 'http://graph.facebook.com/'$iduser;  

<?php
   $iduser = $_GET['iduser'];
   $currsiteurl = "http://graph.facebook.com/${iduser}";

?>

should work hope this helps.

You have a syntax error.

 $currsiteurl = 'http://graph.facebook.com/' . $iduser; 

you forgot the concatination . between string and variable:

$currsiteurl = 'http://graph.facebook.com/' . $iduser;

should work

Use this code

<?php  
 $iduser=$_GET['iduser'];
 $currsiteurl = 'http://graph.facebook.com/'.$iduser; 
?>

You have to use '.' to join string in php