I would like to hide the last two sections from an IP address using regular expression the problem is that the asterix (*) must match the length of those sections.
Eg: 10.101.12.100 should be re-formated into 10.101.**.***
This is the code I'm working with :
echo preg_replace('!(\d+).(\d+).\d+.\d+!s', '${1}.${2}.***.***', "10.101.12.100");
// Return: 10.101.***.***
Is that possible using regex ?
PS: I know I could break it using explode('.', ...) along with str_repeat('*', strlen(...)) but I find preg_replace a cleaner solution. I'm looking for a "oneliner" solution.
Use a negative look-ahead (Basically, have regex disqualify the first two octets, then do a normal digit replace from thereafter.) e.g.
(?!\d{1,3}\.\d{1,3}\.)\d
Example output:
237.134.85.92 -> 237.134.**.**
173.14.176.182 -> 173.14.***.***
167.209.41.203 -> 167.209.**.***
137.133.204.130 -> 137.133.***.***
93.108.72.157 -> 93.108.**.***
That might be a bit of an abuse of a regex. The following is probably faster, safer, and easier to understand...