如果使用href获得两个php函数,如何调用特定的php函数

//Login.php
function display_login_form(){
   //..Code
}

function handle_login(){
   //..Code
}

-------------------------------------------------
//AddSubject.php
//No include any header
function handle_addsub_form(){
    //..Some code
    echo <<<SUCCESSRESPONSE
    <html>
        <head>
            <title>New Subject record inserted</title>
            <link rel="stylesheet" type="text/css" href="./css/mycss.css">
        </head>
        <body>
            <h1 id="white">Creation of Subject</h1>
            <h3 id="white">Created entry for subject $subjectcode $title</h3>

            <br/>
            <a href="XXXXXX">//<=== go to first php function handle_login()
                <span id="white">Home</span>
            </a>
        </body>  
    </html>
SUCCESSRESPONSE;
}

From my code above, i assume everybody understand my question right? how i go to specific function only

Because if i just input It will just go to the first function and i would like to go only specific function and ignore the rest of it. it's possible to do it?

You can check if the form was submitted. Something like:

<?php
if(isset($_POST)){
    handle_login();    
} else {
    display_login_form();
}
?>

In PHP you don't "go to" a function, you call it. Your PHP code needs some logic to know which function to call. You can add query string parameters, use a form, there are many ways. You have to write some logic though, it's not a built in feature.

You can pass the name of function you want to execute and put it in switch statement.

$fn = $_REQUEST['fn'];

switch($fn){
   case "handleLogin":
    handleLogin();
   break;
   default:
    echo "function not found";
   break;
}