如何用js将数组中的数据补全

如开始时间为5：00，结束时间为24：00，将传过来的数组
timeArray:['6:05','6:15','6:20','6:25','6:40','6:45','6:55','7:00','8:00','9:00'],
inStation:[10,20,50,60,40,70,50,80,20,10],
outStation:[30,40,35,65,0,40,20,30,10,20]
补成timeArray:
['5:00','5:05','5:10',5:15'',····'6:05','6:10',6:15','6:20','6:25','6:30','6:35',6:40','6:45','6:50','6:55','7:00','7:05',········'8:00',········'24:00'],
inStation:[0,0,········10,0,20,50,60,40,70,50,80,20,10],
outStation:[0,0,········30,40,35,65,0,40,20,30,10,20]
多出的时间间隔将数值补0

下面给你一段JS，你自己看看

function printTime() {
    // 不知道你timeArray需要干什么
    // var timeArray = new Array('6:05','6:15','6:20','6:25','6:40','6:45','6:55','7:00','8:00','9:00');
    var time = "";
    for (var i = 5; i <= 23; i++) {
        for (var j = 0; j < 12; j++) {
            var min = "";
            if (j <= 1) {
                min = "0";
            }
            time = i + ":" + min + (j * 5);
            console.log(time);
        }
    }
    time = "24:00";
    console.log(time);
}

不用补，直接输出这个数组不就成了

直接重新生成一个数组比补数组方便多了