从table1中选择3个值并使用table2中table1中的一个值来获取结果?

Hi Stackoverflow members!

I got this dilemma:

users  ID  username  firstname  middlename lastname
        1  bilbodog    Casper               Thomsen
        2  bilbodog2   Smith      John      Andersen


flirts    flirter_id  flirted_id  date  time
              1          2          X    X

I wanna get all the flirted_id's made by the flirter_id '1' and compare the flirted_id to users and gather the firstname, middlename & lastname from the flirted_id. Plus I wanna gather the date and time from the flirts table. Then I wanna echo the results out in a HTML table.

So for now I am doing this:

<?php
$ID=$_SESSION['ID'];
// Create connection
$conn = new mysqli($mysql_hostname, $mysql_user, $mysql_password, $mysql_database);
// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT flirted_id, date, time FROM flirts WHERE flirter_id='$ID'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
  ----> ECHO TABLE <----
} else {
  echo 'No flirts found.';
}
$conn->close();
?>

But that does not work.

I am so stuck at this point. I dunno how to gather 3 results from 1 table and use one of the results to compare at table 2, to gather the firstname, middlename and lastname of the person that goes by that ID.

  • Thanks in advance!
</div>

If I understand you correctly you want to do a join to grab the information from table1 and also the information about the person in table 2 who is listed as added_id in table1

select t1.date, t1.time, t2.first, t2.middle, t2.last
from table1 t1
join table2 t2 on (t1.added_id = t2.id)
where t1.adder_id = 1;

If you also want the information about the adder_id (assuming the persons are also stored in table2):

select t1.date, t1.time, t2.first, t2.middle. t2.last, t3.first, t3.middle, t3.last
from table1 t1
join table2 t2 on (t1.added_id = t2.id)
join table2 t3 on (t1.added_id = t3.id)
where t1.adder_id = 1;    

In this case you should give the person cols alias to identify them more cleary, e.g. t2.first as added_id_first, t3.first as adder_id_first and so on

Note I assume that there are no NULL values in the adder_id and added_id fields. If they can then use a LEFT JOIN instead of JOIN in the statements.

Try it

select concat (table2.first," ",table2.middle ) as adder_id_Name,AddedName.* from table2,(SELECT concat (tb2.first," ",tb2.middle ) as added_id_Name,  tb1.adder_id from table2 tb2,table1 tb1 where tb1.added_id = tb2.ID) as AddedName where table2.ID = AddedName.adder_id

I found out by myself. I strangled my brain and got this as the answer:

                              <?php
                                    // Create connection
                                    $conn = new mysqli($mysql_hostname, $mysql_user, $mysql_password, $mysql_database);
                                    // Check connection
                                    if ($conn->connect_error) {
                                        die("Connection failed: " . $conn->connect_error);
                                    }
                                        $sql = "SELECT from_id, message, date, time FROM messages WHERE to_id='$ID'";
                                        $result = $conn->query($sql);
                                    if ($result->num_rows > 0) {
                                        // output data of each row
                                        while($row = $result->fetch_assoc()) {
                                            $from_id=$row["from_id"];
                                            $message=$row["message"];
                                            $date=$row["date"];
                                            $time=$row["time"];
                                            $sql10 = "SELECT firstname, middlename, lastname FROM users WHERE ID='$from_id'"; 
                                            $sql11 = mysql_query($sql10); 
                                            $sql12 = mysql_fetch_row($sql11);
                                            $firstname=$sql12[0];
                                            $middlename=$sql12[1];
                                            $lastname=$sql12[2];
                                            ?>
                                            <a href="#" class="list-group-item">
                                                <span class="label label-default"><?php echo $date, ' ', $time; ?></span>
                                                <span class="fa fa-star"></span>
                                                <span class="name" style="min-width: 120px; display: inline-block;">Casper Thomsen</span>
                                                <span class="text-muted" style="font-size: 11px;">- <?php echo $message; ?></span>
                                                <span class="pull-right">
                                                    <button type="submit" id="view_message" name="view_message" class="btn btn-default btn-xs pull-right">L&aelig;s  Besked <i class="fa fa-angle-right"></i></button>
                                                </span>
                                            </a>
                                            <?php
                                        }
                                    } else {
                                        echo '
                                        <div class="block block-team_member_block span12 first cf">
                                            <div class="member">
                                                <div class="member-social">
                                                </div>
                                                <h3>No members or could not connect to database..</h3>
                                                <div class="bline"></div>
                                            </div>
                                        </div>';
                                    }
                                    $conn->close();
                                ?>