Php检查时间字符串整小时是否像“上午8:00”

I have series of time strings like "8:00am", "8:15am", "8:30am" I also have timestamps for these times as keys of the arrays where as times are values so array would be like this:

Note: Timestamps are dummy in this example

array(
144441415=>"8:00am", 
1444784744=>8:30am
...
.....
);

I would like to know if hour is whole hour for example "8:00am", "9:00am" are whole hours but "8:45am" or "9:30am" are not whole hours. I would like to filter whole hours from array as mentioned above. Thanks.

Thank you Rudie I was able to get whole hour from number of seconds, thank you for your hint, so I did something like this:

//Loop through each hour of the day by getting both key and value
foreach( $hours_of_day $timestamp=>$time_string )
{
    //If timestamp mod by number of seconds in hours is zero this means whole hour
    if( ($timestamp%3600) == 0 )
    {
        echo "Whole hour = $timestring<br />";
    }
}

You could do something like this:

$times = array(
    144441415=>"8:00am", 
    1444784744=>"8:30am",
    1444784745=>"8:45am",
    1444784746=>"9:00am",
    1444784747=>"10:00am",

);

foreach ($times as $time) {
    if (date("H:00:00", strtotime($time)) == date("H:i:00", strtotime($time))) {
        echo '<br>Whole Hour: '.$time;
    }
    else {
        echo '<br>Not Whole Hour: '. $time;
    }
}

For the ones who may encounter this question, the best way to achieve this is the following:

define("BR", "<br />");
$data = array(
    144441415=>"8:00am", 
    1444784744=>"8:30am"
);

$tmp_dto; 
$tmp_mins;

foreach($data as $hour){
    $tmp_dto = DateTime::createFromFormat("H:iA", $hour);
    $tmp_mins = $tmp_dto->format("i");
    if($tmp_mins == "00"){
        echo "ROUND".BR;
    } 
    else{
        echo "NOT ROUND".BR;
    }
}

Outputs

ROUND
NOT ROUND