如何用数组中的多个＃替换？

I'm not exactly sure what this is called but is common in programming, often using the ? instead of the % which I use in this example.

Say I have a string:

"How many % does it take the build a % out of aluminum cans?"

And I want to replace the % symbol with specific values from an array based on their index and the position in the string. In this case:

['robots', 'laser gun']

The result would be:

How many robots does it take to build a laser gun out of aluminum cans?

Is there any way to easily accomplish this in PHP?

just adding to the options :-)

<?php

$s=    "How many  %1\$s does it take the build a  %2\$s out of aluminum cans?";
$a=array('robots', 'laser gun');

echo vsprintf($s,$a)
?>

I wrote this up and tested it, works!

$randomstring = "How many % does it take the build a % out of aluminum cans?";

$array = array("robots", "laser gun");

for($x = 0;$x != count($array);$x++){
   $randomstring = preg_replace('/%/', $array[$x], $randomstring, 1);
}

echo $randomstring;

Perhaps

sprintf ( "How many %s does it take the build a %s out of aluminum cans?", "robots", "laser gun" )

sprintf

The following code does the job:

$string = 'How many % does it take the build a % out of aluminum cans?';
$placeholders = ['robots', 'laser gun'];
echo call_user_func_array('sprintf', array_merge([str_replace('%', '%s', $string)], $placeholders));

If you label the tokens then you can use strtr to search and replace the values. Using named tokens makes your code slightly easier to read.

$str = "How many {thing} does it take the build a {weapon} out of aluminum cans?";

echo strtr($str, [
    '{thing}'  => 'robots',
    '{weapon}' => 'laser gun',
]);