How can I remove the remaining part of a string after certain characters like ?, #, &, %, = in PHP? Any ideas? I tried preg_replace(), but I couldn't figure it out.
Update, just realized I read it wrong. You're looking for stuff before, not after. Updated code:
$test_string = 'remember?forget';
preg_match('/([^?#&%=]+)/', $test_string, $matches);
$part_before_char = $matches[1];
After run, $part_before_char = 'remember'
$str = 'mystring#deletedpartofstring';
$str = preg_replace('/[?#&%=].+/', '', $str);
This should work:
$str = "Hello World#somesuffixstr";
preg_match("/^(.*?[?#&%=]).*/", $str, $str);
echo $str[1];
// Should output "Hello World#"
About the regex pattern:
It searches for beginning of string (^), then for any character 0 or more times (which is group #1), then such a symbol like & or %, then any character zero or more times. It replaces the string with the characters matched in group #1.