数组格式如下,期望的结果是保留后面三笔,因为前面两笔重复了,希望去除重复,谢谢!!!
可以定义一个 map,然后遍历一遍数组,如果根据 id 判断是否在 Map 中,完成一遍去重后,再将该 Map 转成数组。参考 demo:
var result = {};
for(var i=0;i<array.length;i++){
var current = array[i];
//不存在,则存储到 Map 中
if(result[current.deviceId] == undefined){
result[current.deviceId] = current;
}
}
//在将 Map 转成数组
var uniqueArray = [];
var allKeys = Object.getOwnPropertyNames(result);
for (var i = 0; i < allKeys.length; i++){
uniqueArray.push(result[allKeys[i]);
}
如果数据少,不考虑效率,两重循环,和已经添加到结果数组的比较下
var result = [];
if (array.length == 0) return;
result.push(array[0]);
for (var i = 1; i < array.length; i++)
{
var found = false;
for (var j = 0; j < result.length; j++)
{ if (array[i].deviceId == result[j].deviceId) {found = true; break}; }
if (!found) result.push(array[i]);
}
let newArr = [];
array.filter(item =>{if(!newArr.some(ele=>ele.deviceId===item.deviceId)){newArr.push(item)}});
console.log(newArr)