我如何在PHP中专门使用套接字端口

I am looking for a method to prevent other scripts to reuse tcp port I am using for listening.

$socket = stream_socket_server('tcp://0.0.0.0:8196', $errcode, $errtxt);

This line will create a server socket which means nobody can use 8196 port. However I can open more sockets or the same port. Why? How I can prevent this?