Phalcon - 创建一个新的文件实例

In phalcon you can get uploaded file with this piece of code

//Check if the user has uploaded files
if ($this->request->hasFiles() == true) {
    //Print the real file names and their sizes
    foreach ($this->request->getUploadedFiles() as $file){
        echo $file->getName(), " ", $file->getSize(), "
";
    }
}

each $file is an Phalcon\Http\Request\File instance.

But what if I want to create an file instance from an existing file on the server, how can I do that?

What I tried is this:

new Phalcon\Http\Request\File(array($fileDir));

But it returns an instance with empty properties.

any help would be appreciated :D

As per the documentation of that class I think the constructor does not expect an array. So just leave out the array( ) that you are passing to the constructor and you should be fine. Disclaimer: I did not check out the code and rely on the documentation being proper here.

Code example:

new Phalcon\Http\Request\File($fileDir);

But what if I want to create an file instance from an existing file on the server, how can I do that?

This class is designed to work with $_FILES superglobal, so as for me you are using wrong tool. I would create your own wrapper for using files that are already on server, or go for SplFileObject.

Anyway, how should parameter array look like you may be able to anderstand from here starting at line 74+ and it pretty reflects $_FILES structure.