如何匹配非引用的东西？

I have the following RegEx to remove commentary from a PHP file: %/\*.*?\*/%s

The side effect is, that on use of glob like glob($basedir . '/*') it starts removing everything midcode...

So how do I tell the regex to not match when there are quotes in front of it or behind it?

Try this :

%[^'"]{1}/\*.*?\*/[^'"]{1}%s

It include not simple or double quote before /* and after */