下注 (bet)(1s,512MB)

题目描述
小 A 是赌狗。
这天小 A 遇到了 2n 个人，他们打算和小 A 赌扔一枚硬币的结果。具体来说，对于第 i 个人，小 A可以选择在开始的时候给 ta 1 元下注，如果 i ≤ n，则最终结果为正面时，小 A 可以得到返还的 Ai 元，否则不会得到收益；如果 i > n，则最终结果为反面时，小 A 可以得到返还的 Ai 元，否则不会得到收益。小 A 这几天已经输麻了，于是打算稳一把，她想问问你在最坏情况下获得的收益最大可以是多少?

【以下回答由 GPT 生成】

Sure, I can assist Little A in optimizing her betting strategy using C++. Here's a step-by-step solution:

Step 1: Input the number of individuals, n, and the corresponding returns, A[i].

Step 2: Sort the returns in descending order, such that the highest return is in the first position.

Step 3: Calculate the maximum profit by summing up the returns from the largest n individuals.

Step 4: Print the maximum profit.

Here's the code implementation in C++:

#include <iostream>
#include <algorithm>

using namespace std;

bool compare(int a, int b) {
    return a > b;
}

int main() {
    int n;
    cin >> n;

    int A[2 * n];
    for (int i = 0; i < 2 * n; ++i) {
        cin >> A[i];
    }

    sort(A, A + 2 * n, compare);

    int maxProfit = 0;
    for (int i = 0; i < n; ++i) {
        maxProfit += A[i];
    }

    cout << "Maximum profit that can be achieved: " << maxProfit << endl;

    return 0;
}

This code will ask for the number of individuals, n, and their respective returns, A[i]. It will then sort the returns in descending order using the compare function. Finally, it will calculate the maximum profit by summing up the returns from the largest n individuals and print the result.

Note: This solution assumes that the input is valid and that n is within the range of the array A. It also assumes that the returns are integers.