C语言这道问题怎么写啊

#include <stdio.h>
#include <math.h>

int isTriangle(float x1, float y1, float x2, float y2, float x3, float y3) {
    float side1, side2, side3;

    side1 = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
    side2 = sqrt(pow(x3 - x2, 2) + pow(y3 - y2, 2));
    side3 = sqrt(pow(x1 - x3, 2) + pow(y1 - y3, 2));

    if (side1 + side2 > side3 && side2 + side3 > side1 && side3 + side1 > side2) {
        return 1;
    } else {
        return 0;
    }
}

void classifyTriangle(float x1, float y1, float x2, float y2, float x3, float y3) {
    float side1, side2, side3;

    side1 = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
    side2 = sqrt(pow(x3 - x2, 2) + pow(y3 - y2, 2));
    side3 = sqrt(pow(x1 - x3, 2) + pow(y1 - y3, 2));

    if (side1 == side2 && side2 == side3) {
        printf("等边三角形\n");
    } else if (side1 == side2 || side2 == side3 || side3 == side1) {
        if (pow(side1, 2) == pow(side2, 2) + pow(side3, 2) ||
            pow(side2, 2) == pow(side1, 2) + pow(side3, 2) ||
            pow(side3, 2) == pow(side1, 2) + pow(side2, 2)) {
            printf("等腰直角三角形\n");
        } else {
            printf("等腰三角形\n");
        }
    } else if (pow(side1, 2) == pow(side2, 2) + pow(side3, 2) ||
               pow(side2, 2) == pow(side1, 2) + pow(side3, 2) ||
               pow(side3, 2) == pow(side1, 2) + pow(side2, 2)) {
        printf("直角三角形\n");
    } else {
        printf("普通三角形\n");
    }
}

int main() {
    float x1, y1, x2, y2, x3, y3;

    printf("请输入第一个点的坐标(x1, y1): ");
    scanf("%f %f", &x1, &y1);
    printf("请输入第二个点的坐标(x2, y2): ");
    scanf("%f %f", &x2, &y2);
    printf("请输入第三个点的坐标(x3, y3): ");
    scanf("%f %f", &x3, &y3);

    if (isTriangle(x1, y1, x2, y2, x3, y3)) {
        classifyTriangle(x1, y1, x2, y2, x3, y3);
    } else {
        printf("这三个点不能构成一个三角形\n");
    }

    return 0;
}