列出脚本文件中的所有类和方法

I would like to output to an array all classes and their methods names as well as method type (public, private, protected) to an array after picking a particular script file.

This will be used to create a permissions system, where an admin can specify what classes a particular user group may access.

For instance say in the script file test.php it has the following:

class test{

public function dostuff(){

}

private function hide(){

}
}

It should give me a list like this: class: test methods: dostuff (public) hide (private)

OK, this is what I'd suggest :

// Get new class name

$classes = get_declared_classes();
include 'your_php_file.php';
$diff = array_diff(get_declared_classes(), $classes);
$class = reset($diff);

// Get class's methods

$methods = get_class_methods($class);

// Print them out

echo "Class : ".$class;
foreach ($methods as $method) {
    echo "$method
";
}

<?php
$file="test_class.php";
$fp = fopen($file, 'r');
$class = $buffer = '';
$method = $buffer = '';
while(!feof($fp))
{
    $buffer .= fread($fp, 512);
    if (preg_match('/class\s+(\w+)(.*)?\{/', $buffer, $matches)) {
        $class = $matches[1];
        //break;
    }
    if (preg_match_all('/function\s+(\w+)(.*)?\{/', $buffer, $match)) {
        $method = $match[1];
        //print_r($match);
        //break;
    }
}


echo "class:".$class."<br />";
//print_r($method);
foreach($method as $key=>$val)
{
echo "method : ".$val."<br />";
}

?>